0=16x^2-64x+57

Solution for 0=16x^2-64x+57 equation:

0=16x^2-64x+57

We move all terms to the left:

0-(16x^2-64x+57)=0

We add all the numbers together, and all the variables

-(16x^2-64x+57)=0

We get rid of parentheses

-16x^2+64x-57=0

a = -16; b = 64; c = -57;
Δ = b2-4ac
Δ = 642-4·(-16)·(-57)
Δ = 448
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{448}=\sqrt{64*7}=\sqrt{64}*\sqrt{7}=8\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-8\sqrt{7}}{2*-16}=\frac{-64-8\sqrt{7}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+8\sqrt{7}}{2*-16}=\frac{-64+8\sqrt{7}}{-32}
$